关于oracle中的group by

Posted by 猪头小队长 | 程序设计 | Wednesday 29 September 2004 10:16
有这样一张表(buy_detail),存放的是用户的购物信息,字段buyTime是购物时间,精确到秒。
现在要统计用户每天的消费情况:
select name,to_char(buyTime,’YYYYMMDD’) as ti , sum(cost)
from buy_detail
group by name,ti
这样做是有语法错误的,应该为:
select name,to_char(buyTime,’YYYYMMDD’) as ti , sum(cost)
from buy_detail
group by name,to_char(buyTime,’YYYYMMDD’)

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